answer:Sure! Here's an example of a calculator with the functionalities you mentioned, implemented using a switch-case solution in Python: ```python def arithmetic_operation(num1, num2, operator): result = 0 if operator == '+': result = num1 + num2 elif operator == '-': result = num1 - num2 elif operator == '*': result = num1 * num2 elif operator == '/': result = num1 / num2 return result def compare_numbers(num1, num2): if num1 > num2: return f"{num1} is greater than {num2}" elif num1 < num2: return f"{num1} is less than {num2}" else: return f"{num1} is equal to {num2}" def find_percentage(num, percentage): return (num * percentage) / 100 def find_power(base, exponent): return base ** exponent def convert_to_decimal(number, base): decimal = 0 power = 0 while number > 0: digit = number % 10 decimal += digit * (base ** power) number //= 10 power += 1 return decimal # Main calculator function def calculator(): print("Calculator Functionalities:") print("1. Arithmetic Operation") print("2. Comparison") print("3. Percentage") print("4. Power") print("5. Conversion to Decimal") choice = input("Enter your choice (1-5): ") if choice == '1': num1 = float(input("Enter the first number: ")) num2 = float(input("Enter the second number: ")) operator = input("Enter the arithmetic operator (+, -, *, /): ") result = arithmetic_operation(num1, num2, operator) print(f"The result is: {result}") elif choice == '2': num1 = float(input("Enter the first number: ")) num2 = float(input("Enter the second number: ")) result = compare_numbers(num1, num2) print(result) elif choice == '3': num = float(input("Enter the number: ")) percentage = float(input("Enter the percentage: ")) result = find_percentage(num, percentage) print(f"{percentage}% of {num} is: {result}") elif choice == '4': base = float(input("Enter the base number: ")) exponent = float(input("Enter the exponent: ")) result = find_power(base, exponent) print(f"{base} raised to the power of {exponent} is: {result}") elif choice == '5': number = int(input("Enter the number: ")) base = int(input("Enter the base of the number system: ")) result = convert_to_decimal(number, base) print(f"The decimal equivalent of {number} in base {base} is: {result}") else: print("Invalid choice! Please select a number from 1 to 5.") # Run the calculator calculator() ``` Hope this helps! Let me know if you have any further questions.

answer:要提升火星的温度，可以考虑以下方法： 1. 温室效应增强：类似地球上的温室效应，加强火星大气中的温室气体含量，例如二氧化碳。这可以通过引入大量二氧化碳或其他温室气体到火星大气中来实现。这将有助于捕获和保留太阳辐射，提高火星的表面温度。 2. 人工增加火星大气厚度：火星目前的大气非常稀薄，没有足够的厚度来保留和分散太阳辐射。通过向火星大气中释放大量气体(例如氮气或氧气)，可以增加大气厚度，从而改善温室效应并提高表面温度。 3. 地壳上升：通过地球科学技术，可以将地壳从地下层抬升到火星表面。这样可以释放地下储存的温暖能量，并提高火星的表面温度。 4. 日光镜：在火星上放置镜子或其他反射材料，将太阳辐射反射到火星表面。这将增加火星的接收太阳能量，并提高表面温度。 需要注意的是，这些方法仅仅是理论上的建议，实际操作涉及到巨大的工程和技术挑战。此外，提升火星的温度可能引发其他复杂的环境影响，需要进行深入的研究和评估。

answer:Here's an example of a calculator program using a switch case to handle the functionalities you mentioned: ```python def arithmetic_operation(x, y, operator): if operator == '+': return x + y elif operator == '-': return x - y elif operator == '*': return x * y elif operator == '/': return x / y else: return "Invalid operator" def compare_numbers(x, y): if x > y: return f"{x} is greater than {y}" elif x < y: return f"{x} is smaller than {y}" else: return f"{x} is equal to {y}" def calculate_percentage(x, y): return (x * y) / 100 def calculate_power(x, y): return pow(x, y) def convert_to_decimal(num, base): decimal = 0 power = 0 while num > 0: remainder = num % 10 decimal += remainder * pow(base, power) num //= 10 power += 1 return decimal def calculator(): print("Calculator Menu:") print("1. Arithmetic Operation") print("2. Compare Numbers") print("3. Calculate Percentage") print("4. Calculate Power") print("5. Convert to Decimal") choice = int(input("Enter your choice (1-5): ")) if choice in range(1, 6): if choice == 1: x = float(input("Enter first number: ")) y = float(input("Enter second number: ")) operator = input("Enter operator (+, -, *, /): ") result = arithmetic_operation(x, y, operator) print("Result: ", result) elif choice == 2: x = float(input("Enter first number: ")) y = float(input("Enter second number: ")) result = compare_numbers(x, y) print(result) elif choice == 3: x = float(input("Enter the number: ")) y = float(input("Enter the percentage: ")) result = calculate_percentage(x, y) print("Percentage: ", result) elif choice == 4: x = float(input("Enter the base number: ")) y = float(input("Enter the exponent: ")) result = calculate_power(x, y) print("Result: ", result) elif choice == 5: num = int(input("Enter the number: ")) base = int(input("Enter the base (2-9): ")) result = convert_to_decimal(num, base) print("Decimal: ", result) else: print("Invalid choice. Please try again.") calculator() ``` This program allows the user to select from various functionalities using a switch case implementation in Python. The program prompts the user for inputs based on the selected functionality and provides the result accordingly.

answer:Sure! Here's an updated version of the calculator program using code blocks and a switch case solution: ```python def arithmetic_operation(x, y, operator): return { '+': x + y, '-': x - y, '*': x * y, '/': x / y, }.get(operator, "Invalid operator") def compare_numbers(x, y): return f"{x} is greater than {y}" if x > y else f"{x} is smaller than {y}" if x < y else f"{x} is equal to {y}" def calculate_percentage(x, y): return (x * y) / 100 def calculate_power(x, y): return pow(x, y) def convert_to_decimal(num, base): try: decimal = int(str(num), base) return decimal except ValueError: return "Invalid input" def calculator(): print("Calculator Menu:") print("1. Arithmetic Operation") print("2. Compare Numbers") print("3. Calculate Percentage") print("4. Calculate Power") print("5. Convert to Decimal") choice = int(input("Enter your choice (1-5): ")) if choice in range(1, 6): if choice == 1: x = float(input("Enter first number: ")) y = float(input("Enter second number: ")) operator = input("Enter operator (+, -, *, /): ") result = arithmetic_operation(x, y, operator) print("Result: ", result) elif choice == 2: x = float(input("Enter first number: ")) y = float(input("Enter second number: ")) result = compare_numbers(x, y) print(result) elif choice == 3: x = float(input("Enter the number: ")) y = float(input("Enter the percentage: ")) result = calculate_percentage(x, y) print("Percentage: ", result) elif choice == 4: x = float(input("Enter the base number: ")) y = float(input("Enter the exponent: ")) result = calculate_power(x, y) print("Result: ", result) elif choice == 5: num = input("Enter the number: ") base = int(input("Enter the base (2-36): ")) result = convert_to_decimal(num, base) print("Decimal: ", result) else: print("Invalid choice. Please try again.") calculator() ``` In this updated version, I used a dictionary to map the arithmetic operators in the `arithmetic_operation` function. I also included a `try-except` block in the `convert_to_decimal` function to handle invalid inputs. The program now supports easy conversion from other number systems to decimal using `int(str(num), base)`. Note: The number base in the `convert_to_decimal` function is limited to 2-36, as using characters beyond that range would require complex handling or additional libraries.